Algebra problem words

The last example is a word problem that requires an equation with variables on both sides. Flor and Mo both donated money to the same charity. To turn this into a problem we can solve, we'll have to translate it into math.

Problem 2 Here's another problem to do on your own. We'll solve it the same way we solved the problem on page 1. How many minutes were charged on this bill?

The key word "same" in this problem means that I am going to set my two expressions equal to each other. Step 5: Check the problem.

Hard algebra word problems

The best part is When we set the two expressions equal, we now have an equation with variables on both sides. To get the correct answer, we'll have to get m alone on one side of the equation. Here's how: Because we've already said we'll represent the amount of Mo's donation with the variable m, let's start by replacing Mo's donation with m. To make sure we solved the problem correctly, we should check our work. Assessment Want even more practice? Here's how: First, replace the cost of a family pass with our variable f. This time, the important facts are highlighted. Let's look at an example of an algebra word problem. You can solve these problems the same way we solved the first one—just follow the problem-solving steps we covered earlier. Step 3: Translate the rest of the problem Let's look at the problem again. Write an equation to represent the total ticket sales. I'm hoping that these three examples will help you as you solve real world problems in Algebra!

The rate does not change; therefore, it is not associated with a variable. When we set the two expressions equal, we now have an equation with variables on both sides.